x^2-8x-92=0

Solution for x^2-8x-92=0 equation:

x^2-8x-92=0

a = 1; b = -8; c = -92;
Δ = b2-4ac
Δ = -82-4·1·(-92)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-12\sqrt{3}}{2*1}=\frac{8-12\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+12\sqrt{3}}{2*1}=\frac{8+12\sqrt{3}}{2}
$